What mass of water (in grams) is produced by the reaction of 74.0g of SiO2? Chemistry help!?
4hf + sio2 ---> sif4 + 2h2o
determine moles of sulfur dioxide
n(sio2) = 74.0 g / 60.08 g/mol = 1.23 mol
determine moles of water using mole ratio
n(h2o) = 2 x n(sio2) = (2)(1.232) = 2.46 mol
determine mass of water multiplying moles molar mass
(2.46 mol)(18.02 g/mol) = 44.4 g h2o
what mass of water (in grams) produced reaction of 74.0g of sio2 ?
reaction being:
4hf + sio2+sif4+2h2o
thank you! please show me how did it, stuck!
Science & Mathematics Chemistry Next
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